Practice: Blocked and Paired Randomized Experiments

Recognition · Interpretation

A matched-pair experiment has 15 pairs. What is the denominator in the standard error of the estimated effect?

2 hints available, least help first.

Hint 1: Retrieval cue

Ask how many independent choices the randomization made.

Hint 2: Concept cue

If both members of a pair could never be treated together, are the 30 observations independent?

Method selection · Direct application · Interpretation

A trial blocks by region. North: 300 units, τ ^ N = 5 . South: 100 units, τ ^ S = 13 .

Compute the size-weighted estimate, compute the equally weighted estimate, and state which quantity each one targets.

Write your answer, then compare it with the worked solution.

2 hints available, least help first.

Hint 1: Retrieval cue

Write the weighted sum ∑ k ( N k / N ) τ ^ k with the numbers in it.

Hint 2: Strategy cue

For each average, say in words which collection of things it is an average over.

Compare with the worked solution

Comparing does not record a result. Judging your own written answer cannot show that you can do this without help.

Size-weighted. τ ^ = 300 400 ( 5 ) + 100 400 ( 13 ) = 3.75 + 3.25 = 7.0 .

Equally weighted. ( 5 + 13 ) / 2 = 9.0 .

What each targets. The size-weighted figure estimates the average effect over the 400 units actually in the trial: each unit counts once, so the larger region dominates in proportion to its size. The equally weighted figure estimates the average of the two regional effects, giving a region of 100 the same influence as a region of 300.

Which to report. If the question is what the intervention did for the people studied, 7.0 is the answer. The 2.0 gap is a difference of estimand rather than of precision, so reporting 9.0 while describing the average effect on the trial's units misstates what was estimated. Equal weighting is defensible only when the regions are themselves the units of interest, for instance if each region is a site whose policy is decided separately.

Was blocking worth it here? It depends on how strongly region predicts the outcome. Blocking removes between-region variation from the comparison, so it reduces variance in proportion to how much of the outcome region explains. If the two regional effects had been close and region weakly prognostic, the design would have committed the analysis to a stratified estimator for little gain.

A complete answer does each of these:

  • applies design estimator
  • weights match estimand
  • detects design discarded
  • justifies blocking choice

Comparison · Recognition

Which of these is a blocked randomized design?

2 hints available, least help first.

Hint 1: Retrieval cue

Ask when the grouping happened relative to assignment.

Hint 2: Concept cue

Blocking is a property of the design. Did anyone randomize within the groups?

Error diagnosis · Explanation · Evaluation

An analyst writes:

We ran a matched-pair experiment with 20 pairs. For the analysis we compared the 20 treated units against the 20 control units with a two-sample t-test, since once the data are collected the pairing no longer matters.

Identify the error and explain what it costs.

Write your answer, then compare it with the worked solution.

2 hints available, least help first.

Hint 1: Retrieval cue

List the allocations this design could have produced.

Hint 2: Concept cue

Ask what the pooled spread contains that the within-pair differences do not.

Compare with the worked solution

Comparing does not record a result. Judging your own written answer cannot show that you can do this without help.

The error. The claim reverses the relationship between design and analysis. Pairing is not a feature of data collection that can be set aside afterwards; it is a restriction on which allocations were possible, and that restriction governs every later calculation.

What the design permitted. One choice per pair, so 2 20 allocations, about a million, not ( 40 20 ) , which is roughly 138 billion. The two-sample test refers to a reference distribution over allocations the experiment could never have produced, including every allocation treating both members of some pair.

What it costs in precision. The two-sample standard error is computed from the spread of raw outcomes across all 40 units. That spread contains the between-pair variation the matching was designed to remove: whatever the two members of a pair shared cancels exactly in their difference but not in a pooled comparison. If the pairs were well matched, the raw outcomes vary considerably more than the differences do, so the standard error is inflated and the result looks weaker than the design earned.

The correct analysis. Work on the 20 differences D j = Y j , T − Y j , C : τ ^ = D ¯ , S E = s D / 20 , compared against t on 19 degrees of freedom, or a randomization test enumerating the 2 20 sign flips.

Why the design cannot be set aside. Pairing was chosen because the pairing variable was expected to predict the outcome; that expectation is what the precision gain rests on. Having accepted the constraint, the analysis is committed to it, which is exactly what the two-sample test ignores. A design is not advice that can be declined at the analysis stage.

A complete answer does each of these:

  • applies design estimator
  • weights match estimand
  • detects design discarded
  • justifies blocking choice

Transfer · Evaluation · Explanation

An agricultural trial divides each of 8 fields into two halves and randomly assigns one half of each field to a new fertiliser. The agronomist reports the mean yield of all treated halves against all control halves, with a standard error from the pooled spread across the 16 half-fields.

Say what the design was, what the analysis should have been, and what the reported standard error describes.

Write your answer, then compare it with the worked solution.

2 hints available, least help first.

Hint 1: Retrieval cue

Ask what was randomized, and how many independent choices were made.

Hint 2: Strategy cue

Ask what the two halves of one field have in common, and whether that cancels in a difference.

Compare with the worked solution

Comparing does not record a result. Judging your own written answer cannot show that you can do this without help.

The design. A matched-pair experiment with the field as the block: 8 fields, one coin per field, J = 8 pairs. The vocabulary is agricultural and the structure is the one this unit covers.

The analysis it requires. Work on the 8 within-field differences D j , giving τ ^ = D ¯ and S E ( τ ^ ) = s D / 8 , against t on 7 degrees of freedom, or a randomization test over the 2 8 = 256 allocations the design permitted.

Why the field is the right block. Soil composition, drainage, slope and microclimate are shared by the two halves of a field and differ substantially between fields. Those shared characteristics cancel exactly in a within-field difference. The pooled spread across 16 half-fields contains all of that between-field variation, which is precisely what the design arranged to remove.

What the reported standard error describes. An experiment in which 16 half-fields were independently assigned to fertiliser, which is not what happened, since assigning one half of a field determined the other. It will typically overstate the uncertainty, understating what the trial established, and its reference distribution belongs to an experiment that was never run.

Why halves of a field. Soil and drainage vary far more between fields than within one, so the field is strongly prognostic and splitting it removes that variation by construction. That is the case where blocking earns its constraint, and having earned it, the analysis owes the paired estimator rather than a pooled comparison.

A complete answer does each of these:

  • applies design estimator
  • weights match estimand
  • detects design discarded
  • justifies blocking choice
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